Physics: Post your doubts here!

[Thought blocker]

Can you please elaborate it a bit more,
also can you please tell why ans is not B

Its simple dude, Because it is itself the formula of electric field strength---->E=v/d
I cannot elaborate more ._.
If mehria kitkat <3 :P sagar65265 Suchal Riaz may explain in detail

 

[Mohammed salik]

i still cnt believe that u r 15

Wow..! How Should I Prove it ? :/!

 

[Thought blocker]

Wow..! How Should I Prove it ? :/!

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w13_qp_13.pdf
Solve Q22 fast I wanna check my method ._.

 

[Mohammed salik]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_13.pdf
Solve Q22 fast I wanna check my method ._.

Give Me Few Minutes ..! Busy Hoon !

 

[Thought blocker]

Give Me Few Minutes ..! Busy Hoon !

Jaldi please.

 

[mehria]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_13.pdf
Solve Q22 fast I wanna check my method ._.

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w13_qp_13.pdf

Can anyone please explain Q22 and 31

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

 

[Mohammed salik]

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

Yeh Cheez..! Sorry Yaar..! I was About to Start Typing !

 

[Thought blocker]

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

Yes did the same way

 

[Mohammed salik]

Jaldi please.

Yeh Cheez..! Sorry Yaar..! I was About to Start Typing !

 

[Thought blocker]

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

 

[mehria]

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

ur statement is correct
due to same force actng on each charge the electric field strength is also same for both...

 

[Mohammed salik]

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

Derivation f Formula E = v / d ? :-

 

[Thought blocker]

ur statement is correct
due to same force actng on each charge the electric field strength is also same for both...

Derivation f Formula E = v / d ? :-

But that guy needs more elaboration, I know I am correct, but I can't elaborate more then that ._.

 

[mehria]

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

it is all abt E= F/Q.. not E=V/d

 

[mehria]

But that guy needs more elaboration, I know I am correct, but I can't elaborate more then that ._.

but E=V/d is for the charges that are present between two oppositely chargd plates.. where as in ths question we r nt told that the charge is placed in between the two oppositely chrgd plates so we will work out our ans by considering E=F/Q

 

[Mohammed salik]

Look For Formula E= V/d ... First thing is You Have to Know Electric Field= F/q
Work Done is = F * d
And We Know Voltage or EMF= Workdone ( w)/ Unit Charge (q)
So We can Say W=Voltage * Charge
Then
F*d=V*q
F/q=V/d
So we can Say E= v/d!!
And You did Give Him correct Explanation ..! Where Exactly His confusion is ?

But that guy needs more elaboration, I know I am correct, but I can't elaborate more then that ._.

 

[Thought blocker]

it is all abt E= F/Q.. not E=V/d

but E=V/d is for the charges that are present between two oppositely chargd plates.. where as in ths question we r nt told that the charge is placed in between the two oppositely chrgd plates so we will work out our ans by considering E=F/Q

I mean to say is it is formula based question yaar :/

 

[Thought blocker]

Look For Formula E= V/d ... First thing is You Have to Know Electric Field= F/q
Work Done is = F * d
And We Know Voltage or EMF= Workdone ( w)/ Unit Charge (q)
So We can Say W=Voltage * Charge
Then
F*d=V*q
F/q=V/d
So we can Say E= v/d!!
And You did Give Him correct Explanation ..! Where Exactly His confusion is ?

Bas I think now it might be clear

 

[MYLORD]

If any1 could help me with these doubts

 

[mehria]

If any1 could help me with these doubts


View attachment 43767 View attachment 43768 View attachment 43769 View attachment 43770 View attachment 43771 View attachment 43772

can u share the link...?