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Physics: Post your doubts here!

Mayisha M

Mayisha M

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XPFMember said:
Hi everyone, AsSalamoAlaikum Wr Wb...

To get things organized in a better way, I am making this thread. As othewise, some queries remain unanswered!

So post your PHYSICS doubts in this thread. InshaAllah other people here will help me and you all. :D ;)

NOTE: If any doubts in the pastpapers, please post the link! You can find links here!

Any Physics related notes and links will be added here in this post. Feel free to provide the links to your notes around the forum, or any other websites! :)
Thanks!
Jazak Allah Khair!

Physics Notes:

Some links & Notes - by destined007

As physics p1 MCQS YEARLY Solved [explaination]
Physics Practical Tips - by arlery

Notes for A2 Direct Sensing (Applications) - shared by sweetiepie

Physics Summarised Notes (Click to download)

AS and A-Level Physics Definitions

A2: Physics Revision notes - by smzimran

Paper:5 Finding uncerainty in log - by XPFMember

Physics Paper 5 tips - by arlery

Physics Compiled Pastpapers: <Credits to CaptainDanger for sharing this..>

Here are the compiled A level topical Physics questions in PDF form...

Paper 1 : http://www.mediafire.com/?tocg6ha6ihkwd

Paper 2 & Paper 4 : http://www.mediafire.com/?g65j51stacmy33c

(Source : http://www.alevelforum.com/viewtopic.php?f=15&t=14)
Click to expand...

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w13_qp_21.pdf
Someone help me understand question 5 (a)(ii) where they ask you to find the amplitude?
I've solved like tonnes of papers and never saw sth like this -.-
Please help.
Also, if Im not being such a bother, explain 5(b) to me as well?
Thanks :)
 
Mayisha M

Mayisha M

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umair1161 said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_23.pdf

Question 3 (a) please!

Thanks in advance! :)
Click to expand...


Hi :)
This is really easy, you just have to understand that it's a curve and you can't use definite shape areas to calculate the distance travelled.
You use this process called counting squares, which the mark schemes use as well. E.g. just count the number of complete 10×10 squares that are present. And then make a rough estimate of the number of 10 × 10 squares that could be occupied by the others. In this case, the number of complete 10 × 10 squares I assumed was 7 + 2.75. It's just an approximation you have to make by judging the size of the square covered by the curve. The area represented by each 10 × 10 square is (2*2 =) 4 m. Therefore,

distance moved = area under curve = (number of 10 × 10 squares) × (Area under each 10 × 10 square)
= (9.75) × (4)
= 39m.

Hope you get me. Cheers.
 
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Browny

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Mayisha M said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_21.pdf
Someone help me understand question 5 (a)(ii) where they ask you to find the amplitude?
I've solved like tonnes of papers and never saw sth like this -.-
Please help.
Also, if Im not being such a bother, explain 5(b) to me as well?
Thanks :)
Click to expand...
They are saying that point A moves 80mm. Point A is a point on the rope and it is not moving sideways but only moving up and down.
So it moves 80mm first going up to amplitude then it goes back to equilibrium position back down to a trough and back up so the actual amplitude is 80/4=20.:)
 
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Browny

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umair1161

umair1161

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Mayisha M said:
Hi :)
This is really easy, you just have to understand that it's a curve and you can't use definite shape areas to calculate the distance travelled.
You use this process called counting squares, which the mark schemes use as well. E.g. just count the number of complete 10×10 squares that are present. And then make a rough estimate of the number of 10 × 10 squares that could be occupied by the others. In this case, the number of complete 10 × 10 squares I assumed was 7 + 2.75. It's just an approximation you have to make by judging the size of the square covered by the curve. The area represented by each 10 × 10 square is (2*2 =) 4 m. Therefore,

distance moved = area under curve = (number of 10 × 10 squares) × (Area under each 10 × 10 square)
= (9.75) × (4)
= 39m.

Hope you get me. Cheers.
Click to expand...


Was it that simple?!?! :O

Thanks man! Really helpful! :)
 
ZaqZainab

ZaqZainab

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