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Biology; Chemistry; Physics: Post your doubts here!

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http://papers.xtremepapers.com/CIE/Cambridge International O Level/Biology (5090)/5090_s08_qp_6.pdf please someone tell me how to calculate surface area of given cubes in question no.1 part a.
1st cube...all six sides exposed...1cm x 6. = 6.....2nd cube has been cut into eight pieces.... area of each side of one block 0.5x0.5 = 0.25......0.25x 6sides= 1.5...total 8 blocks so 8x1.5= 12......3rd cube has been cut into two equal pieces...... dimensions of one block are now 1x1x0.5.....upper part and base is 1cmx1cm so 1x 2 sides=2cm....the other 4 sides are 0.5x1....so 4(1xo.5)..=2cm.....total area of one cube =4 and 2 cubes =8......
 
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If we decrease the distance on the left side by moving the screw in, the perpendicular distance on that side will be decreased..Now as may know that moment is directly proportional to the perpendicular distance the moment on the left side is lesser so left side goes up and the flattened end goes down..
Hope u got it..
i know what you are trying to say but perpendicular distance will not matter unless there is equal force on both sides.....
 
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ahan but thn what abt total poppulation any idea
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Note the volume of the yeast used to make the slide and count the number of cells in that particular volume which are visible in the microscope. Multiply that by the total volume of yeast in the exp.
 
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1st cube...all six sides exposed...1cm x 6. = 6.....2nd cube has been cut into eight pieces.... area of each side of one block 0.5x0.5 = 0.25......0.25x 6sides= 1.5...total 8 blocks so 8x1.5= 12......3rd cube has been cut into two equal pieces...... dimensions of one block are now 1x1x0.5.....upper part and base is 1cmx1cm so 1x 2 sides=2cm....the other 4 sides are 0.5x1....so 4(1xo.5)..=2cm.....total area of one cube =4 and 2 cubes =8......
Alright so we have to take all sides of each cube not just the sides exposed?
 
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In ATPs if the points plotted on the graph are in the form of an uneven curve, we can simply join them with a rule right?
 
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