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No prob!thanks....!
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No prob!thanks....!
can u solve just q18 u know what i solved this already but for ur effort i am highly grateful to uAlright, it's a bit lengthy, so have patience with me!
First, note that A travels 3m and B travels 2.8m. This means that for the first 2.8m of the journey, A travels with exactly the same speed as B. After 2.8m, the Tension in the string eliminates, which causes A to decelerate. We have to find this speed, after the deceleration.
So, we start off by construction of two equations for A and B for the first 2.8m
For A, it is
T - 20 = 4a
For B, it is
30 - T = 3a
Add both equations, T gets eliminated, and the value of a retained is 10/7 m/s^2.
Now you find out the speed of A after 2.8m. The value of a we found may be helpful as we could simply use the formula 2as = v^2 - u^2. Remember to take s as 2.8m, and not 3m. The value of v hence comes out as 2.82 m/s.
Now, as T is no more in the string, put T = 0 N in the equation we built for A. This gives us -20 = 4a, hence the value of a now becomes -5 m/s^2
Use these values now to find the final speed. u would be 2.82 m/s, a would be -5 m/s^2, and s would be 0.2m.
The answer comes out as 2.46 m/s. There might have been a problem with me as I rounded off figures for easy calculation. If you use exact figures, you'll get exactly the same answer. For this question, I suspect that you'll have to use g as 9.81 m/s^2. However, you may know better!
I hope this helps!
i heard from many of my friends and from friends who actually did edexcel they say that maths edexcel is easier by lots! they say cie math is so complicated while edexcel maths is simple ! but personally i do not know!does anyone have any ideas whether cie is easier than edexcel in Maths?
does anyone have any ideas whether cie is easier than edexcel in Maths?
Integrate with respect to x:
q1. (4-x) / (x-2) (x-3)
q2. 1 / (x^2 -4)
Plz reply as soon as possible.
These had been posted on the forum before, I just had them downloaded!Need notes for P1 plz. ASAP...
guys can any one explain how to calculate the range for a function.........i stil dun knw how to calculate it...!
1) calculate the first derevative of the functionguys can any one explain how to calculate the range for a function.........i stil dun knw how to calculate it...!
they already said leave the answer in surds..so when u do the equation x= -b ±√(b^2-4ac) / 2a u will end up with x =1/4 (-20 + √40) or 1/4(-20-√40) u can simplify it..did u get it now ?So here's this question in quadratics ..
solve the quadratic equation leaving in surds form ..
i know we have to solve with the abc formula .. but this equation does not fit in .. help please :\
---> 2(x+3)^2 = 5
I have rationalized the denominator, it is although not necessary!So here's this question in quadratics ..
solve the quadratic equation leaving in surds form ..
i know we have to solve with the abc formula .. but this equation does not fit in .. help please :\
---> 2(x+3)^2 = 5
dude tht is for stationary point of a curve.... no?1) calculate the first derevative of the function
2) equate it to zero
3) find the X- value and this the the x-coordinate of the maximum or the minimum of the range
4) find the second derevative of the function and substitute the x value if needed, if its -ve, y is at max for value of x found in step 3 and if +ve value of y is at minimum.
5) substitute your x value in the original function to find Y value needed
6) if step 4 was +ve then Y grater than or equal to value found in step 5, and if step four was -ve, then Y is smaller than or equal to value of step 5.
Hope it helps.
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