• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
75
Reaction score
48
Points
28
A giant squid of length 20.0m is vertical in seawater, with the top of the squid at a depth of
8.00m. The density of seawater is 1050kgm–3.
What is the difference in pressure between the top and the bottom of the squid?
A 82000Pa B 206000Pa C 288000Pa D 389000Pa
Anyone?
use the pressure formula= density*g*depth
use depth as 20m
 
Messages
75
Reaction score
48
Points
28
Q19.
Ans=C
first find the power produced by the engine itself. so using force*velocity=power hence 30000/25=1200N
notice the car maintains 25m/s therefore forces are balanced and there is no net force.
we need to calculate the weight down the slope.
so 1400*g*sin(2)=479.3.....N
the car has to overcome this force to maintain a constant velocity and it does this by producing an extra output power of 479.3....N*25=12000watts
so total output power= 12000+30000=42000
 
Messages
75
Reaction score
48
Points
28
can anyone please explain this?View attachment 62515
we first need to find the voltage in the external resistance. so using v=ir
hence v=5.5v. since the all of the components are parallel to each other they all have an terminal potential difference of 5.5v
current going into the junction= output of junction.
so the current going into the internal resistance is 0.25A. 0.5/2 as both components have the same p.d and internal resistance they both have the same current
simply then use the formual
terminal p.d=Emf-Ir
5.5=6-0.25r
hence r is 2 ohms
 
Messages
36
Reaction score
19
Points
8
we first need to find the voltage in the external resistance. so using v=ir
hence v=5.5v. since the all of the components are parallel to each other they all have an terminal potential difference of 5.5v
current going into the junction= output of junction.
so the current going into the internal resistance is 0.25A. 0.5/2 as both components have the same p.d and internal resistance they both have the same current
simply then use the formual
terminal p.d=Emf-Ir
5.5=6-0.25r
hence r is 2 ohms
Thanks
 
Top