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so the waves entering the double slit should be coherent( having constant phase diff example 2lamda) or in phase?( 0 phase difference )Yes it is always zero when the waves are in phase.
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so the waves entering the double slit should be coherent( having constant phase diff example 2lamda) or in phase?( 0 phase difference )Yes it is always zero when the waves are in phase.
Still not there in that chapter.so the waves entering the double slit should be coherent( having constant phase diff example 2lamda) or in phase?( 0 phase difference )
ITS A!i wish but i checked again and it is still not the answer. it is question no. 5 of may june 2005.
here is the link
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_ms_1.pdf
Hey, I have a question regarding Paper 5.
So in question 1, where a method of data analysis is required to be mentioned, the most common one is the graph.
Now, I know that it is mandatory to mention the variables plotted in the graph. But are we allowed to use derived variables?
I'll explain with an example...
S14 - Paper 51
The equation provided is T^2 = constant x (C-R)
where C and R are variables. The question asks us to investigate the relationship between T and R, for which I decided to draw a graph with (C-R) in the X axis and T^2 in the Y axis.
However, the marking scheme states that a graph of T^2 against R should be drawn. The analysis provided is also according to this. My analysis is different, for my graph is different.
I was wondering if, since my answer is different, would I gain the same credit as the answer in the marking scheme? Or would I not?
Nope.is my displacement time graph for this situation okay?View attachment 51290View attachment 51291
View attachment 51303 View attachment 51304
View attachment 51305
Can someone please explain these questions?
The answer is C in the first 2 and D in the last btw
For other answer,View attachment 51303 View attachment 51304
Can someone please explain these questions?
The answer is C in both btw
oh my god! thankyou so much. i dont know whats wrong with me
20:View attachment 51303 View attachment 51304
View attachment 51305
Can someone please explain these questions?
The answer is C in the first 2 and D in the last btw
Nothing's wrong with you.oh my god! thankyou so much. i dont know whats wrong with me
Thanks!Young Modulus is same as material is same. Therefore as young's modulus = (f / a) * ( l /e). This can be used in both wires.
(60*l)/((d^2) * 8 ) = (60 * (l /4))/(((d^2)/4) * e)
where d = diameter
l = original length
e = extension to be found.
when you simplify above equation then you get e = 8 mm
Look in the text book.
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