Physics: Post your doubts here!

[princesszahra]

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s10_qp_13.pdf

Question 26

Help please

use fleming's left hand rule ( as current is the cause of motion)
so field directed away from the observer, current will be opposite to the motion electron beam as electrons are -ve!
so the motion is downwards!

refer to the figure below
sorry if i'm wrong!!but i think my concepts still work!!!

 

[mahadamjad18]

may june 2003 qs 5 :Yahoo!:

 

[rz123]

http://www.xtremepapers.com/CIE/Interna ... _qp_51.pdf

q.1 how to design this experiment..

 

[XPFMember]

http://www.xtremepapers.com/CIE/Interna ... _qp_51.pdf

q.1 how to design this experiment..

Assalamoalaikum..
I'm posting my answer what I wrote..I hope it's correct

In this experiment, velocity 'v' is the independent variable and the depth 'd' is the dependent variable.

The mass of the object hitting the nail must be kept constant. Also the same type of nail and wood must be used throughout.

Change the height from which the mass is falling to change the velocity, v. Use a plastic tube, so that the mass is allowed to fall vertically down at the nail. Use a set-square to ensure that the plastic tube is vertical. Use a ruler to determine the height, h. Hence use the energy conservation equation, v^2 = 2gh , to determine the velocity of the mass at the instant when it hits the nail.
Note the length of the nail at the start of the experiment using a 30cm ruler.
After the mass has hit the nail, mark the point above the wood, and hence find the length of the nail above the wood surface.

Find the difference of these two lengths to obtain the value of d.
Repeat this procedure with different heights and obtain at least six readings. Use each part of wood only once. Repeat the experiment twice for each value of d and find the average for further processing the results.
Plot the graph of log d against log v. The graph will be a straight line. (Draw a sketch of it! ) The gradient gives the value of n

Taking log of the equation d = kv^n => log d = n log v + log k

 

[rz123]

^salaam and thanks a lot

 

[rz123]

http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s10_qp_13.pdf

Question 26

Help please

plz somebody explain the answer in a better way !

 

[rz123]

lots of problems. someone help ...
http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

mcqs : 8, 15, 18, 19, 27, 33, 38 . just need a short brief description . . . thanks a lot.

 

[maybeitwasnoone]

lots of problems. someone help ...
http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

mcqs : 8, 15, 18, 19, 27, 33, 38 . just need a short brief description . . . thanks a lot.

Question 8, draw a tangent at t=3 and find the value

Question 19, Young's Modulus= Stress/Strain, substitute 3*10^8/5 You get D

Question 38 would be A since a Beta particle is emitted which means to the original nuclide there'd be an addition of one proton while the number of neutrons will remain the same.

 

[rz123]

thanks bro ^

 

[unique840]

lots of problems. someone help ...
http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

mcqs : 8, 15, 18, 19, 27, 33, 38 . just need a short brief description . . . thanks a lot.

15) power = force * velocity
hook = 1000 N
load = 1000 * 10 = 10000 N
total force = 11000 N
11000*0.5 = 5.5kW

18) it contracts, so distance will decrease and water has a higher density than ice

 

[unique840]

lots of problems. someone help ...
http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

mcqs : 8, 15, 18, 19, 27, 33, 38 . just need a short brief description . . . thanks a lot.

19) its 5%, not 5. 3*10^8 / 5%

 

[unique840]

lots of problems. someone help ...
http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

mcqs : 8, 15, 18, 19, 27, 33, 38 . just need a short brief description . . . thanks a lot.

38) neutrons n protons are 4

 

[rz123]

thanks a lot dude!!! it really helped me! all clear

 

[unique840]

thanks a lot dude!!! it really helped me! all clear

ur welcum

 

[unique840]

lots of problems. someone help ...
http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

mcqs : 8, 15, 18, 19, 27, 33, 38 . just need a short brief description . . . thanks a lot.

33) resistance is same. P have current I. Q AND R have current I/2. power is I^2 * R
I^2 * R + (I/2)^2 * R + (1/2)^2 * R = 12
(3/2) I^2 * R = 12
I^2 * R = 8
for R, power is (I/2)^2 * R = (I^2 * R)/4
8/4
2W

 

[rz123]

u rock :wink: ^
some more from paper 21 http://www.xtremepapers.com/CIE/Interna ... _qp_21.pdf

Q.3 b i , 3 b iii , 5b ii label the region D Thanks!

 

[a021011]

http://www.xtremepapers.com/CIE/Interna ... 9_ms_2.pdf

Paper 21, Please Explain Question 5b

 

[maybeitwasnoone]

thanks bro ^

Your welcome, unfortunately for you, I'm no bro.

 

[rz123]

ohh ok doesn't matter.hope u can solve the other questions i posted if u get some time. Thanks a bunch!

 

[unique840]

u rock :wink: ^
some more from paper 21 http://www.xtremepapers.com/CIE/Interna ... _qp_21.pdf

Q.3 b i , 3 b iii , 5b ii label the region D Thanks!

3b iii) k.e = (1/2) mv^2
momentum = mv
(p^2)/2m = (m^2 * v^2) / 2m
= (m * v^2) / 2
= k.e