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Mathematics: Post your doubts here!

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View attachment 59139
How to do part iii please??? :O
S14-32
12647498_1674651716131574_2747872781883847119_n.jpg
 
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To find the normal, how did you get the (0,1,0)?
Also multiplying BC into the j i.e (1,1,-4) * (0,1,0) wouldn't it give (0,1,0) ... how does it give (4,0,1)? :p

Lol ... this is vector multiplication, you can't just multiply like that normally. :p And the result is a cross product of two vectors ... I'll just post a pic of how to do it.

12654337_1674751856121560_6575034966872776260_n.jpg


Don't mind the pencil mapping thing ... i tried visually doing the multiplication ... looks like a mess. :p

And yes, I'm doing that coz the cross product of two vectors gives you a 3rd vector that is perpendicular to both the original 2 vectors you are multiplying.

So in your question, if the vector is perpendicular to both j and BC, then it is also perpendicular to the plane. I've taken j since we have not been given any other information sufficient to solve the problem. So we get n and voila! You have your eqn of the plane. B|
 
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Konstantino Nikolas, could u pls help me one more time :cry::cry:
Q8 part iv)...the ans is 259N
and Q9 part iii and iv.... the answers are for iii) T=30,8.87 and for iv) its 1.23kg
plsss...
 

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Lol ... this is vector multiplication, you can't just multiply like that normally. :p And the result is a cross product of two vectors ... I'll just post a pic of how to do it.

12654337_1674751856121560_6575034966872776260_n.jpg


Don't mind the pencil mapping thing ... i tried visually doing the multiplication ... looks like a mess. :p

And yes, I'm doing that coz the cross product of two vectors gives you a 3rd vector that is perpendicular to both the original 2 vectors you are multiplying.

So in your question, if the vector is perpendicular to both j and BC, then it is also perpendicular to the plane. I've taken j since we have not been given any other information sufficient to solve the problem. So we get n and voila! You have your eqn of the plane. B|
:cool: *Like a boss* (y)
Thanksss :p
Ohh yes I usually try to avoid that cross multiplication and just use the ratio's to find the normal :p
 
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