total time = 552s
total distance 12000m
graph forms a trapezium .....through area of trapezium i cudnt get the corect ans so i used the area of rectangle - area of two triangles (T1 and T3)
AREA OF RECTANGLE= total time * velocity = 552 *V
Distance of T1 (triangle T1) = (s=ut +1/2at^2) = 0 + (0.5 *0.3 *(V/0.3)^2) = 5/3 V
Distance of second triangle T3= (s=ut - 1/2 at^2) = V^2 - 1/2 V^2 = 1/2 V^2 (negative sign with a as it is decelerating)
now subtract distances obtained above (triangle T1 and T3) from 552V and equate it with 12000
552 V- (5/3 V +1/2 V^2) = 12000
552 V- 13/6 V^2 =12000 (LCM =6)
3312 V - 13 V^2 =72000
13 V^2 -3312 +72000 (ANS)
.... plz
