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plzz help him talhaYou technically copied what was written in the mark scheme. I would write something like this:
tan^2@ - sin^2@ is always greater than zero for the values of theta between 0 to 90. Hence,
tan^2@ - sin^2@ > 0
tan^2@ > sin^2@
tan@ > sin@
Now that I think about it, you did write everything that is required plus it is just worth one mark so you aren't expected to do much working. So that should be enough
10i) u-w =4i ----1 and uw = 5--------2
I guess its ok u just explained a bit moreYou technically copied what was written in the mark scheme. I would write something like this:
tan^2@ - sin^2@ is always greater than zero for the values of theta between 0 to 90. Hence,
tan^2@ - sin^2@ > 0
tan^2@ > sin^2@
tan@ > sin@
Now that I think about it, you did write everything that is required plus it is just worth one mark so you aren't expected to do much working. So that should be enough
anyways thanks
I posted the same question darling but u didnt read it properly and just kept on choking one-one function.Its okay it happens.Leave it now!
how come u r doing p3?
i still insist it was ur frst question... hahahaahah choking
I hope this is correct, I had seen this solution somewhere, and I memorize it
u better concentrate on p1.I hope this is correct, I had seen this solution somewhere, and I memorize it
I am through with p1
Aaahhhh! Stop pls! You're going to kill me.I lose you win.Im not in the mood of arguing.My next question is : What was the formula for calculating the angle between a tangent and curve.Remember?
.
Thanks alot
( we have to remove the +- to do that look at the domain if it says x≥ hen we use + if it says x≤ then we use - ) I didn't understand what you mean by this can you explain it in details please
and for Q6(ii) I also got 0.31 but in ms it is given +-0.31 ? from where "-" came ?! ..
and for Q8(iii) It is given in the ms C =5 however I got it -4/15 too !!
and for Q8 no the ms doesn't say c=5 :/ it means to say 'intergrated part'+c=y
link of the question do
That's also a correct method, but I prefer this.I really needed this
BTW how did you do i)
i mean i did some thing like this:
tan(pi-x)
=tan(pi) -tan(x)
= 0 - k
=-k
Is this wrong?
Is that an identity? If yes, is it included in syllabus of p1, i freaking find alot of identities out of syllabus. I mean we are supposed to know only two identities:
tan(x)= sin(x)/cos(x), and [sin^2 (x)] * [cos^2 (x)] = 1
So this mean the onto functions only have Inverse?
yes.
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