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Mathematics: Post your doubts here!

Rizwan Javed

Rizwan Javed

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husnain99 said:
Would be appreciated if someone could solve/explain the correct answers ..
Click to expand...
When two quantities are being divided, and you need to find the lower bound for the resulting quantity, then you take the lower bound for the dividend, and the upper bound for the divisor.

Here the Circumference is the dividend, so take its lower bound, which is 104.5 cm. The divisor is radius so take it's upper bound (34.5/2).

So the lower bound for pi would be :

104.5/(34.5/2 * 2)
= 3.029
 
Rizwan Javed

Rizwan Javed

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husnain99 said:
Would be appreciated if someone could solve/explain the correct answers ..
Click to expand...
For finding the upper bound when two quantities are being divided, take the upper bound for the dividend, and the lower bound for the divisors.

Here take the upper bound for the Volume, which will be 555. Take the lower bound for the height, which will be 11.5.

So the upper bound for the radius will be:

( 555 / (pi*11.5) )^1/2
= 3.919
 
husnain99

husnain99

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Rizwan Javed said:
For finding the upper bound when two quantities are being divided, take the upper bound for the dividend, and the lower bound for the divisors.

Here take the upper bound for the Volume, which will be 555. Take the lower bound for the height, which will be 11.5.

So the upper bound for the radius will be:

( 555 / (pi*11.5) )^1/2
= 3.919
Click to expand...
Thank you bro :)
 
husnain99

husnain99

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Rizwan Javed can you please help me to find 'nth term ' for part D only ..


Plus can you please quote all the formulas for pattern and no sequence ?
Thanks
 

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Rizwan Javed

Rizwan Javed

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husnain99 said:
Rizwan Javed can you please help me to find 'nth term ' for part D only ..
Thanks

Plus can you please quote all the formulas for pattern and no sequence ?
Thanks
Click to expand...
The sequence in the D part forms a geometric progression, where every next term is calculated by multiplying the previous term with a common ratio (which is 3 here). So the nth term will be:

first term * (common ratio) ^ n-1

here first term is 2 and the common ratio is 3 (common ratio is calculated by dividing the two consecutive terms)

nth term = 2 * 3 ^(n-1)

-----
to explain this, let me show you what exactly is happening:

2
2 * 3
2 * 3 * 3
2 * 3 * 3 * 3
...

^ You can see that for obtaining every next term you need to multiply the previous one with 3 here. For calculating the 2nd term you need to multiply the first term with only 3. for 3rd you need to multiply with 3^2. For 4th, 3^3 and so on. You can see it yourself that for obtaining nth term you'll have to multiply the first term by 3^n-1.
 
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