1. The papers section has been updated with the latest CIE May/June 2015 resources for most of the subjects.

    Click here for more information or to discuss
    Dismiss Notice

How was your maths 42 M1

Discussion in 'International A And AS Level' started by hellodjfos;s'ff, May 16, 2018.

  1. muaz_ali

    muaz_ali

    Messages:
    122
    Likes Received:
    55
    Trophy Points:
    38
    Gender:
    Male
    Location:
    Lahore
    the answer was btw, 1200=60P +80/2(5.5^2-4^2)
     
  2. XPC Bot

    Sponsored Listings
  3. soccerlover

    soccerlover

    Messages:
    4
    Likes Received:
    0
    Trophy Points:
    1
    btw for the last question i put all my answers in 2 sig figures becuase i got exact values but everyone said that i was supposed to put them in 3 sig figures? will my answers be considered wrong?
     
  4. muaz_ali

    muaz_ali

    Messages:
    122
    Likes Received:
    55
    Trophy Points:
    38
    Gender:
    Male
    Location:
    Lahore
    not at all, it is fine
     
  5. soccerlover

    soccerlover

    Messages:
    4
    Likes Received:
    0
    Trophy Points:
    1
    is did it in a different way, i first found acceleration using v^2-u^2=2ax and found the a and then used the a in the equation work/distance-P=ma
     
  6. DudeWithoutName

    DudeWithoutName

    Messages:
    34
    Likes Received:
    16
    Trophy Points:
    8
    Gender:
    Male
    Itll be accepted no worries
     
  7. hellodjfos;s'ff

    hellodjfos;s'ff

    Messages:
    245
    Likes Received:
    104
    Trophy Points:
    43
    Gender:
    Male
    Alright tell me the questions 1, 2,5. 1 being the resistance P question, 2 being the train and power question, 5 being the coefficient of friction question.
     
  8. DudeWithoutName

    DudeWithoutName

    Messages:
    34
    Likes Received:
    16
    Trophy Points:
    8
    Gender:
    Male
    Challenge accepted

    1)A runner of mass 80kg increases his speed from 4ms^-1 to 5.5ms^1 against a restistive force P over a distance of 60m. Total work done is 1200J. Find the value of P
    2)A train of mass 240000kg travels up a slope inclined at 4 degrees to the horizontal. The resistance to the train's motion is 18000N. At the instant when its speed is 15ms^-1, its deceleration is 0.2ms^-2. Find the power of the train's engine
    5)A particle of mass 20kg is on rough plane inclined at 60 degrees to the horizontal. A force of magnitude P which is parallel to the line of greatest slope of the inclined plane is applied to to the particle to "maintain equilibrium" the greatest value of P is twice the smallest value of P. Find the coefficient of friction between the particle and the plane

    Edit: My memory serves me well I see
     
  9. Niroboy119

    Niroboy119

    Messages:
    8
    Likes Received:
    2
    Trophy Points:
    3
    Gender:
    Male
    that's vry specific and accurate. the answer was 10.5N right.
     
  10. hellodjfos;s'ff

    hellodjfos;s'ff

    Messages:
    245
    Likes Received:
    104
    Trophy Points:
    43
    Gender:
    Male
    U sure the angle in Q2 is correct brow?
     
  11. DudeWithoutName

    DudeWithoutName

    Messages:
    34
    Likes Received:
    16
    Trophy Points:
    8
    Gender:
    Male
    yes you can try to solve it now
     
  12. muaz_ali

    muaz_ali

    Messages:
    122
    Likes Received:
    55
    Trophy Points:
    38
    Gender:
    Male
    Location:
    Lahore
    dude for what price did you buy it, i might need p3 as well.
     
  13. hellodjfos;s'ff

    hellodjfos;s'ff

    Messages:
    245
    Likes Received:
    104
    Trophy Points:
    43
    Gender:
    Male
    Ok can someone help me out on this:
    My friend showed me his working for question 1. He put gain in kinetic+work done by runner=1200J(he claims that the paper said the work done by runner and achieving increase in speed was 1200J). He then found the driving force of the runner. Put that driving force into F=ma to find P. It looks right to me but he is getting 1N for P. What's he doing wrong, I can't spot it
     
  14. muaz_ali

    muaz_ali

    Messages:
    122
    Likes Received:
    55
    Trophy Points:
    38
    Gender:
    Male
    Location:
    Lahore
    1200 not only included the work done in increasing the velocity but also against the resistance.
     
  15. ArchmageShalidor

    ArchmageShalidor

    Messages:
    9
    Likes Received:
    0
    Trophy Points:
    1
    Gender:
    Male
    The total work done by the runner is the gain in K.E and the work done against resistance to motion , which is the product of the constant resistive force and the distance travelled. So in this case,
    1200=K.E+(60*P)
     
  16. hellodjfos;s'ff

    hellodjfos;s'ff

    Messages:
    245
    Likes Received:
    104
    Trophy Points:
    43
    Gender:
    Male
    Ok, he misread the question and I don't remember the full question either :LOL:
     
    iamhereforfun likes this.
  17. iamhereforfun

    iamhereforfun

    Messages:
    10
    Likes Received:
    1
    Trophy Points:
    13
    Gender:
    Male
    wasnt the angle 41.4 ? cuz im pretty sure it was cos inverse 3/4 which is 41.4
     
  18. hellodjfos;s'ff

    hellodjfos;s'ff

    Messages:
    245
    Likes Received:
    104
    Trophy Points:
    43
    Gender:
    Male
    Yeas it was
     

Share This Page