Discussion in 'International A And AS Level' started by XPFMember, Sep 29, 2011.
For Question 23
Minimum number of carbon required for isomerism is 4..less than this isomerism can not be done thus, each product having equal carbon will have 4 carbons leading to N=8 so when 8/2=4 carbon each
for question 24
i don't understand it much but from seeing the option C...addition of steam and Conc.H2SO4 leads to removal of the double bond and water being added at the point
the -OH attached is secondary alchohal for it being attached to carbon that has two carbons attached.further on addition of hot acidified KMnO4 it oxidises the secondary alchohal group to ketone and the primary alcohals on each side to carboxylic acid.....You will understand it much better when you draw displayed formulas of the compond given.
Thanks for your help again!!!
i need a help in this question why is it A?
When ever two stages are involved in reaction its ethalpy profile diagram will have two humps in its graph .......as it is stated in the question X-Y is positive thus it will be endo and reactants will have low energy than the products....in Y-Z ethalpy change is neg thus its exo and reactants will have high energy than products as shown in option A
So it can't be B r8
No....no humps in the graph
K thx soo much
https://www.xtremepapers.com/community/threads/as-level-chemistry-mcq-help.47789/ HELP HERE
The balanced equation should be 10Al + 3Ba(NO3)2 = 5Al2O3 + 3BaO + 3N2 , right? therefore we will get a different answer..
plz reply as soon as possible..
Can anyone help me please?
What is involved in the mechanism of the mechanism of the reaction between aqueous sodium hydroxide and 2-bromo-2-methylbutane?
A heterolytic bond fission, attack by an electrophile on a carbanion
B heterolytic bond fission, attack by an nucleophile on a carbocation
C homolytic bond fission, attack by an electrophile on a carbanion
D homolytic bond fission, attack by an nucleophile on a carbocation
2-bromo-2-methylbutane is a tertiary halogenoalkane and will undergo sN1 'unimolecular' via carbocation reactions.
The C-Br bond will be broken heterolytically and a carbocation ion will be formed. The carbocation would then be attacked by the nucleophile (OH-)
I don't have the context of the full question.
But in both equations, the ratio of Ba(NO3)2 and N2 happens to be 1:1. Therefore, it's a coincidence that the answers ended up to be the same.
Can you answer my question please?
are you talking about this question
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