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Chemistry: Post your doubts here!

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When solid ammonium chloride dissociates at a certain temperature in a 0.500dm3 container, ammonia and hydrogen chloride are formed. NH4Cl(s) NH3(g) + HCl(g) The initial amount of ammonium chloride was 1.00mol, and when the system had reached equilibrium there was 0.300mol of ammonium chloride. What is the numerical value of Kc for this reaction under these conditions?
A 0.490 B 1.63 C 1.96 D 3.27
can u plz tell me how to solve it??
 
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When solid ammonium chloride dissociates at a certain temperature in a 0.500dm3 container, ammonia and hydrogen chloride are formed. NH4Cl(s) NH3(g) + HCl(g) The initial amount of ammonium chloride was 1.00mol, and when the system had reached equilibrium there was 0.300mol of ammonium chloride. What is the numerical value of Kc for this reaction under these conditions?
A 0.490 B 1.63 C 1.96 D 3.27
can u plz tell me how to solve it??
Kc = [NH3] * [HCl] / 1

Don't include the concentration of NH4Cl in Kc equation as it is in solid state....
 
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The commonest form of iron(II) sulfate is the heptahydrate, FeSO4.7H2O. On heating at 90 C
this loses some of its water of crystallisation to form a different hydrated form of iron(II) sulfate,
FeSO4.xH2O.
3.40 g of FeSO4.xH2O was dissolved in water to form 250 cm3
of solution.
A 25.0 cm3
sample of this solution was acidifi ed and titrated with 0.0200 mol dm–3 potassium
manganate(VII).
In this titration 20.0 cm3
of this potassium manganate(VII) solution was required to react fully with
the Fe2+ ions present in the sample.
(a) The MnO4

ions in the potassium manganate(VII) oxidise the Fe2+ ions in the acidifi ed solution.
(i) Explain, in terms of electron transfer, the meaning of the term oxidise in the sentence
above.
.............................................................................................................................................
....................................................................................................................................... [1]
(ii) Complete and balance the ionic equation for the reaction between the manganate(VII)
ions and the iron(II) ions.
MnO4

(aq) + 5Fe2+(aq) + .........H+(aq)  .........(aq) + 5Fe3+(aq) + .........H2O(l)
[3]
(b) (i) Calculate the number of moles of manganate(VII) used in the titration.
[1]
(ii) Use the equation in (a)(ii) and your answer to (b)(i) to calculate the number of moles of
Fe2+ present in the 25.0 cm3
sample of solution used.
[1]
(iii) Calculate the number of moles of FeSO4.xH2O in 3.40 g of the compound.
[1]
(iv) Calculate the relative formula mass of FeSO4.xH2O.
[1]
(v) The relative formula mass of anhydrous iron(II) sulfate, FeSO4, is 151.8.
Calculate the value of x in FeSO4.xH2O.
I need help in these question
 
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In these one why 250/25?!?!

3.40 g of the compound was dissolved in 250 cm^3 , and only 25 cm^3 of the 250cm^3 was used in the titration.

So when we need to find the original amount in 250 cm^3 , we need to multiply by a factor of 10
 
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Can someone explain Q2) a) i) for [H+]?
 

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Help please........ the ans is B

Which of these equations represents the reaction of sulphur dioxide with an excess of aqueous

sodium hydroxide?

A SO2 + NaOH ----> NaHSO3

B SO2 + 2NaOH -------> Na2SO3 + H2O

C SO2 + 2NaOH ------> Na2SO4 + H2O

D SO2 + 2NaOH -----> Na2SO4 + H2

Why cant it be reaction C???

Because Na2So4 doesn't exist as a product of that reaction.

However, if you didn't know that, just try looking at the balancing of the equation and see if it works. Out of B and C, only B is correct.
 
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Can anyone help me with this question...Oct Nov 2008 Question:39
 

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28 Compound X will decolourise a warm acidified solution of manganate(VII) ions and forms orange
crystals on reaction with 2,4-dinitrophenylhydrazine.
What is X?
A CH3CH=CHCH2OH
B CH3COCH2CH3
C CH3CH2CH2CHO
D CH3CH(OH)CH2CO2H

And why?
 
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