• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
23
Reaction score
2
Points
3
ok
CH3CH2CH2OH + 4.5O2------>3CO2 + 4H2O
so 0.1 mol propanol reacts with 0.45 mol of the o.5 mol oxygen provided (12dm3 oxygen is 0.5 mol)
0.05 mol of oxygen is left over as gas.
0.3 mol of CO2 is formed which is the gaseous product as H2O will be liquid at r.t.p.
0.35mol of total gases.
0.35x24=8.4dm3 gases in the final mixture under ROOM CONDITIONS.

ok thx
 
Messages
430
Reaction score
144
Points
53
aaa.png
pls explain all briefly. Starting from part (ii)
remember Ag2SO4 partially soluble.
paper is m/j 2015 p43
Thanks!!
 
Messages
1
Reaction score
0
Points
11
2-x : x/2 : x

In essence, it's a pretty simple question if you ask me. People tend to get confused seeing variables instead of constants.

Anyhow.

There are two approaches to this.

One is quicker but much more confusing. If you want, let me know and I'll enlist that too.

If not, simply take the equations and manipulate.

A- Inital: 2 : 0 : 0
Final : 2-x: 2x : x
Total moles: 2-2+2x+x = 3x so A is incorrect.

B-
Initial: 2 : 0 : 0
Final: 2-2x : 2x : x
Total moles: 2-2x+2x+x = 2+x so B is incorrect

C-
Initial: 2 : 0 : 0
Final 2-2x:x:x
Total = 2-2x+x+x = 2

D-
Initial: 2 : 0 : 0
Final: 2-x : x/2 : x [x = 2R]
Total moles = 2-x+x/2+x =2+x/2 mols!

B is correct cuz the ans is 2+x...
 
Messages
5
Reaction score
0
Points
11
Could someone please help me with a problem on May/June 2014/P23...question #2
I am having difficulty understand (iv). It says, "Calculate the amount, in moles, of ammonium ions in the sample of the double salt'. From what I see on the marking scheme, it is saying the NH4+ react with the H+ in a 1:1 ration. I dont understand where this 1:1 ration is coming from? The only equation that is written is
NH4+ + OH- -----> NH3 + H2O

thanks
 

Attachments

  • P23_q2.png
    P23_q2.png
    56.1 KB · Views: 11
Messages
89
Reaction score
15
Points
18
Could someone please help me with a problem on May/June 2014/P23...question #2
I am having difficulty understand (iv). It says, "Calculate the amount, in moles, of ammonium ions in the sample of the double salt'. From what I see on the marking scheme, it is saying the NH4+ react with the H+ in a 1:1 ration. I dont understand where this 1:1 ration is coming from? The only equation that is written is
NH4+ + OH- -----> NH3 + H2O

thanks
 

Attachments

  • 1493315459497-61959202.jpg
    1493315459497-61959202.jpg
    2.5 MB · Views: 17
Messages
23
Reaction score
2
Points
3
Apply alcohol may also be converted into propanol by using a ruthenium (IV) catalyst in water.
CH2=CHCH2OH-> CH3CH2CHO
Suggest what is unusual about this single step ?
ANS : DISPROPORTINATION HAS TAKEN PLACE
How can I know that ? Anyone can explain?
 
Messages
89
Reaction score
15
Points
18
Apply alcohol may also be converted into propanol by using a ruthenium (IV) catalyst in water.
CH2=CHCH2OH-> CH3CH2CHO
Suggest what is unusual about this single step ?
ANS : DISPROPORTINATION HAS TAKEN PLACE
How can I know that ? Anyone can explain?
Because the double bond is reduced and the alcohol group has been oxidised hence the compound has been oxidised and reduced at the same time .
 
Top