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Chemistry: Post your doubts here!

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10.When solid ammonium chloride dissociates at a certain temperature in a 0.500 dm3 container,
ammonia and hydrogen chloride are formed.
NH4Cl (s) NH3(g) + HCl (g)
The initial amount of ammonium chloride was 1.00 mol, and when the system had reached
equilibrium there was 0.300 mol of ammonium chloride.
What is the numerical value of Kc for this reaction under these conditions?
A 0.490 B 1.63 C 1.96 D 3.27
ans is C But how do we get that?
did u get ur ans?
 
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I keep getting D??
NH4Cl is in a solid state! So whenever you want to find kc you only include gaseous and liquid states (Since its concentration) Its like a rule
The 1 mol of NH4Cl decreased to 0.3 (-0.7)
So each of the products increase from 0 to 0.7 moles
Convert that to concentration
0.7/0.5= 1.4 mol/dm3
Apply the formula of Kc
Kc= 1.4*1.4= 1.96 which is C
Get it?
 
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NH4Cl is in a solid state! So whenever you want to find kc you only include gaseous and liquid states (Since its concentration) Its like a rule
The 1 mol of NH4Cl decreased to 0.3 (-0.7)
So each of the products increase from 0 to 0.7 moles
Convert that to concentration
0.7/0.5= 1.4 mol/dm3
Apply the formula of Kc
Kc= 1.4*1.4= 1.96 which is C
Get it?
OOHH! Thanks :LOL:
 
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6 The standard enthalpy change for the reaction
2NF3(g) → 2N(g) + 6F(g) is ΔH
o = +1668 kJ
What is the bond energy of the N–F bond?
A –556 kJ mol–1
B –278 kJ mol–1
C +278 kJ mol–1
D +556 kJ mol–1
Ans is C...How??
 
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39)1 and 2
View attachment 61409
40) This is easiest last question, i ever saw xD Sorry to say like this, but just u have to manipulate its structure and match with the given compound in question. All three is having that formula after oxidation. Try once, if u dont get ask me. Bored in making that one in 39 xD :p
39 Okay, got that :)
40 Yeah okay...but I don't get the 3rd molecule ? ANd hey Q 40 is in the examiner report's particularly difficult :p
 
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39 Okay, got that :)
40 Yeah okay...but I don't get the 3rd molecule ? ANd hey Q 40 is in the examiner report's particularly difficult :p
IDK how i found that easiest -_- This was the paper i gave and the only sure answer was this xD
This is your oxidised product of third molecule. CO2 is product as well, i have just shown that main thingy xD
upload_2016-10-31_23-16-23.png
 
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