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Chemistry: Post your doubts here!

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Please help with this question
an aqueous solution contains 1 mol
of S2O32- ions and this reduces 4
mol of Cl2 molecules. What is the
sulfur containing product of this
reaction a) S (b)SO2 (c) SO32- (d)
SO42-. I cnt just come up with the
solution. Answer is D
 
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Please help with this question
an aqueous solution contains 1 mol
of S2O32- ions and this reduces 4
mol of Cl2 molecules. What is the
sulfur containing product of this
reaction a) S (b)SO2 (c) SO32- (d)
SO42-. I cnt just come up with the
solution. Answer is D
for 1 mole of S203^2- to reduce 4 moles of Cl2 molecules it should give 8 electrons in order to form 8Cl^-
since there are two sulphur in S2O3^2- each sulphur atom gives 4 elecctrons
in S2O3^2- the oxidation number of sulphur is +2. since now sulphur is giving 4 electrons each, its oxidation number becomes +2+4=+6. So find the oxidation number of sulphur in each option & you'll realise only in D sulphur has a oxidation number of +6.
 
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can someone explain why it's D, and not the others
View attachment 55088
A cannot be an answer
B cannot be an answer because exothermic reactions do not require high temperature because exothermic reactions occur readily and at a fast rate unlike endothermic reactions
C cannot be an answer because breaking of a bond is an endothermic reaction not exothermic
 
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Hey,
can anyone upload solved paper 5 questions(graph questions)

-the construction lines part that is and finding out the equations to be used.
thank you.
 
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May June 11 paper 2 and variant 22.
can someone please explain Q1..c i. we get 0.04 moles of acid and alcohol,,dont we subtract it from 0.1 to get moles at equilibrium?
 
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Oct Nov 2003 paper 1

Can anyone explain Q2,3,15 and 20 ??
Q15 - see the ones which will decompose
B - MgCO3 -----> MgO + CO2 ---- u are getting one mole ov a gas which means its 24dm3
C- 2Mg(NO3)2 ------> 2MgO + 4NO2 + O2 ---- here its 5 moles of gas

Q20 -try out the structures....thats the only option
if u dont get it tell me

Q3-- its easy
write the equation first
C6H12 + 9O2 ------> 6CO2 + 6H2O
find the mass of CO2 nd H2O
6CO2 = 108
6H20 = 264
108/264 = .41
 
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Q15 - see the ones which will decompose
B - MgCO3 -----> MgO + CO2 ---- u are getting one mole ov a gas which means its 24dm3
C- 2Mg(NO3)2 ------> 2MgO + 4NO2 + O2 ---- here its 5 moles of gas

Q20 -try out the structures....thats the only option
if u dont get it tell me

Q3-- its easy
write the equation first
C6H12 + 9O2 ------> 6CO2 + 6H2O
find the mass of CO2 nd H2O
6CO2 = 108
6H20 = 264
108/264 = .41
Tysm. .
ur boss is having some doubts in phy mcqs and p2 so I need some help in them :(:cry:
 
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