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Chemistry: Post your doubts here!

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Any Idea how to solve this ... can someone help me please ? :)
 
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anyone explain please ?
In phenyl ethanoic acid u see that there is an addition of carbon,which always means that there must be an addition of CN group which replaced another group,Cl in this case.the addition of carbon is in the form of -CooH which means that CN group was hydrolysed.Rest u just need to learn the reagent and condition.
 
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103
In phenyl ethanoic acid u see that there is an addition of carbon,which always means that there must be an addition of CN group which replaced another group,Cl in this case.the addition of carbon is in the form of -CooH which means that CN group was hydrolysed.Rest u just need to learn the reagent and condition.
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Thanks :) can U help me in this also ? :)
 
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Plz help me with these questions
Octobernovember 2009 paper42 q5 part A.
Octobernovember 2009 paper41 q3 bi and bii
October November 2008 paper4 q2 part b.
THANKS!!
 
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Thanks :) can U help me in this also ? :)
Sorry I can't.all I can say is that for option a charge on the cation will only determine strength of metallic bonding and lattice energy.ratio of charge will only tell the formula.like Mg has charge +2 and cl-1 so compound formula will be mgcl2.Option c seems appropriate.never heard anything like sum of charges so no simply.
 
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Oct 2010 - Q8 - Ca(S) --> Ca(g) is +177
then add ionisation energies 1 and 2 wich are 590 and 1150
then Ca+2(g) --> Ca+2(aq) is -1565
so 117+590+1150-1565 = 352

Q25- a is cracking wich needs 500 degree. b needs reflux in ethanol so high temp needed. c also needs heating. only d doesnt need to be heated.
can you explain Question 8 Oct 2010 please more briefly because I didn't get it
 
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Ohh Thanks ! ^_^ .. btw could You help me in Question 3 and 7 of the same paper please ? :)

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w10_qp_12.pdf

I'm sorry, I don't know how to explain q3.

q7 we know it to be constant temp. that's why we use the formula P x V

initial P x V = final P x V
So it should be flask X + flask Y = final pressure x volume
(P x V of X) +(P x V of Y) = P x V final
(5 x 12000) + (10 x 6000) = 15 x P
thus P = 8000 Pa = 8 kPa so answer is A
 
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I'm sorry, I don't know how to explain q3.

q7 we know it to be constant temp. that's why we use the formula P x V

initial P x V = final P x V
So it should be flask X + flask Y = final pressure x volume
(P x V of X) +(P x V of Y) = P x V final
(5 x 12000) + (10 x 6000) = 15 x P
thus P = 8000 Pa = 8 kPa so answer is A
okay now question 26 :p .. hope I'm not disturbing you
 
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