As physics p1 MCQS YEARLY ONLY.

[Akshajistari]

In my opinion it'd be best if you simply ask specific questions you have trouble with. Doesn't make much sense for me to do a whole paper just in case some of them are difficult. If I do a question it should be one that benefits others...

May/June 2011 Paper 11 Questions 13 , 14 , 27, and 36 please.

 

[qwertypoiu]

May/June 2011 Paper 11 Questions 13 , 14 , 27, and 36 please.

I'll answer soon when I get the time but I also suggest asking them here:
Physics: Post your doubts here!

Another thing, ppl are more likely to reply and help if you ask the questions by posting a pic of it (screen capture), one by one.

 

[Akshajistari]

I'll answer soon when I get the time but I also suggest asking them here:
Physics: Post your doubts here!

Another thing, ppl are more likely to reply and help if you ask the questions by posting a pic of it (screen capture), one by one.

Done, as commanded
https://www.xtremepapers.com/commun...st-your-doubts-here.9860/page-750#post-945956

 

[sj0007]

Done, as commanded
https://www.xtremepapers.com/commun...st-your-doubts-here.9860/page-750#post-945956

Okay and I forgot to mention, I did P1 of the first 9 chp only so I will help u the best I can, most probably I will post the whole solutions by night......... In a few hours........

 

[Akshajistari]

Okay and I forgot to mention, I did P1 of the first 9 chp only so I will help u the best I can, most probably I will post the whole solutions by night......... In a few hours........

Sure! At your convenience is best for me

 

[sj0007]

Sure! At your convenience is best for me

But I guess I am too late
The questions related to the first nine chp r already done, ryt?

 

[Akshajistari]

But I guess I am too late
The questions related to the first nine chp r already done, ryt?

Yep, unfortunately. The other two questions are on Waves and Current Electricity, respectively.

 

[Syed Umar]

5-C
because 3% of 330 = 10 m/s
and speed of sound = 330 m/s
How does this explain it?

 

[Akshajistari]

5-C
because 3% of 330 = 10 m/s
and speed of sound = 330 m/s
How does this explain it?

What question are you referring to ?

 

[Syed Umar]

A 327.7ms–1 B 328ms–1 C 330ms–1 D 300ms–1Which of the following gives her result expressed to the appropriate number of significant figures? A student makes measurements from which she calculates the speed of sound as 327.66ms–1. She estimates that her result is accurate to ±3 %.

 

[Akshajistari]

I think you meant this one Syed Umar ?

Well, the reasoning is that uncertainty is always expressed to 1 significant figure. So, 3% of 327.66 m/s is 10m/s , if you round off to 1 significant figure.
Therefore, the speed should be expressed to the nearest 10, which is the choice C.

I hope I have answered your question satisfactorily

 

[Syed Umar]

View attachment 58100


I think you meant this one Syed Umar ?

Well, the reasoning is that uncertainty is always expressed to 1 significant figure. So, 3% of 327.66 m/s is 10m/s , if you round off to 1 significant figure.
Therefore, the speed should be expressed to the nearest 10, which is the choice C.

I hope I have answered your question satisfactorily

Ohhh, THANKS!

 

[Akshajistari]

Ohhh, THANKS!

You're welcome!

 

[Myaaa_20]

Can someone please explain to me how to questions like question 3 & 4 in Paper 1?
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s15_qp_11.pdf
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s15_ms_11.pdf

 

[Konstantino Nikolas]

Can someone please explain to me how to questions like question 3 & 4 in Paper 1?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s15_qp_11.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s15_ms_11.pdf

Q4: D

They've given us the frequency = 5 Hz
From that, we calculate the time period = 1/f = 0.2 s

Now, from the graph, we know that there is one complete wave in 2 divisions on the time axis.
0.2 s => 2 divisions
1 div => 0.2/2 = 0.1 s

But, the answers are in ms so we need to convert our s value.
0.1 s = 0.1*10^3 ms = 100 ms

Q3 I'm not getting it either will let you know when i do.

 

[Rizwan Javed]

Q4: D

They've given us the frequency = 5 Hz
From that, we calculate the time period = 1/f = 0.2 s

Now, from the graph, we know that there is one complete wave in 2 divisions on the time axis.
0.2 s => 2 divisions
1 div => 0.2/2 = 0.1 s

But, the answers are in ms so we need to convert our s value.
0.1 s = 0.1*10^3 ms = 100 ms

Q3 I'm not getting it either will let you know when i do.

Q:3 : the distance is measure as before. So d will not change. Let the value of the new constant be Kx.
the new equation will be: d = KxV^2
convert the V in this equation to km/h :
d = Kx (1/1000 * 3600)^2
d = 12.96Kx

^substitute this into the original given equation, you'll get:

12.96Kx = k1 v^2

v^2 = 1
so,

12.96Kx = K1
Kx = 0.077162 K1 ~ 0.0772 K1 Ans.

So A is the answer.

 

[Konstantino Nikolas]

Q:3 : the distance is measure as before. So d will not change. Let the value of the new constant be Kx.
the new equation will be: d = KxV^2
convert the V in this equation to km/h :
d = Kx (1/1000 * 3600)^2
d = 12.96Kx

^substitute this into the original given equation, you'll get:

12.96Kx = k1 v^2

v^2 = 1
so,

12.96Kx = K1
Kx = 0.077162 K1 ~ 0.0772 K1 Ans.

So A is the answer.

Oh right! I used 60 instead of 3600 by mistake. Thanks man!

 

[Rizwan Javed]

Oh right! I used 60 instead of 3600 by mistake. Thanks man!

Pleasure

 

[Konstantino Nikolas]

Pleasure

Actually, if I do it this way:

K = d / v^2

K1 = m / (ms^-1)^2 = s^2/m

Kx = m / (1000/3600 ms^-1)^2 = 12.96 s^2/m

Then, Kx = 12.96 K1 right?

 

[Rizwan Javed]

Actually, if I do it this way:

K = d / v^2

K1 = m / (ms^-1)^2 = s^2/m

Kx = m / (1000/3600 ms^-1)^2 = 12.96 s^2/m

Then, Kx = 12.96 K1 right?

you made a mistake in calculation

kx = m / (3600/1000 ms^-1)^2 = m/12.96 (ms^-1)^2 = 0.0772 s^2/m = 0.0772 k1