http://maxpapers.com/syllabus-materials/mathematics-9709-a-level/attachment/9709_s14_qp_51/
Can someone please help me with question 4? Draw a diagram if possible.
Can someone please help me with question 4? Draw a diagram if possible.
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Um, instead of sub x=-6 , why don't u just sub in x=0, that way you can avoid sub in x=1. Anyway when you sub x=0 its suppose to be in 3x^2+14x-5>0 not the earlier modulus. Insert it following this method and you can get the answer.I need help with this question, it's A2 syllabus. I don't understand why the answer is - 5<x<1/3 I thought the answer is x>-5. Can someone please explain step by step please? Thank you.
O to 18 ?If f(x)= (36x^2) -(2x^4)
Find the interval for which f(x) is a decreasing function.
^Can anyone please solve it, along with explanation.
The answer to your first part should be 2(x-3)^2-5Can some1 help me with Question 8 part ( ii ) of this paper ...
http://onlineexamhelp.com/wp-content/uploads/2013/11/9709_s13_qp_11.pdf
The K value is 3 ...
Thanks for the reply, but your answer is totally wrong Anyway, I have solved that question. If you require, following is the solution for it:O to 18 ?
4! * 3! * 2! = 288View attachment 55520
Last Part
Thankx4! * 3! * 2! = 288
There is only 1 person tenors who can stand with Basses. So let symbol 'X' represent Tensors who don't want to stand with basses and X" who wants , and let symbol 'O' represent Basses.
XXX X" OOOO
so if they stand in this arrangement, the number of possible arrangements for tensors, is 3! (taking the X" person stays at his position shown) and the number of possible arrangements for Basses is 4!. As there are two ways in which the teams can stand as a whole i.e: tensors on right and basses on left and vice versa, so multiplying with 2!
So total arrangements become: 3!*4!*2!
f(x)= (6+7x)/(2-x)(1+x^2)= A/(2-x) + Bx+C/(1+x^2)
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