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Recent content by M.Omar
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<----- And no I am not the one with the close-up :P
<----- And no I am not the one with the close-up :P- M.Omar
- Profile post
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RECHECK , REMARKING
well tht is certainly very unexpected! https://drive.google.com/open?id=0B8IFY4QZ6NtbSlY2RGpoWF9VcGs use this link for ur marking schemes..if u r on facebook..then type O/A Level Resources .on that page u,ll find the gts and question papers and mark schemes.... I honestly do not know what to...- M.Omar
- Post #6
- Forum: O-Levels / GCSEs / IGCSE
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RECHECK , REMARKING
What were ur grades if u dont mind telling in the other subs and the one sub or subs u want to recheck?I mean if there is a vast disparity between them then it might mean sth else than rechecking ,mismanagement perhaps but that is assuming that the grades were wrong (in ur view) in more than 2...- M.Omar
- Post #4
- Forum: O-Levels / GCSEs / IGCSE
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RECHECK , REMARKING
Well my brother,s friend,in the prev year, had his pak std paper rechecked because he felt he did not get a fair grade.I believe he was the only one to have a paper recheck from his batch and he infact did get a grade improvement(B to A).Important thing is definitely that one has to be sure of/...- M.Omar
- Post #2
- Forum: O-Levels / GCSEs / IGCSE
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Mathematics: Post your doubts here!
are u sure the question is right ? -
Mathematics: Post your doubts here!
R=180-(P+Q) cos(R)=cos(180-(P+Q))= - cos( P+Q) (from identity cosx=-cos(180-x)) now simply find -cos(P+Q) by using the formula cos(A+B)=cosAcosB-sinAsinB and sinx=(1-(cosx)^2)^(1/2) -
~~jokes?? in here?? really??
an old one.but good in a sick way (for those who get it :P )- M.Omar
- Post #28,518
- Forum: Games and Fun Stuff
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Results: CIE May/June 2016 Examination Series
Ah still the same old xpc community 2 years back ( dint have any result last year) where the first 8-9 pages of the RESULTS thread would be filled with sorrows,anxieties and with countdowns,most prominently a day before the result.Keep it up! :P- M.Omar
- Post #21
- Forum: Announcements
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Results: CIE May/June 2016 Examination Series
Do you have AS results ?- M.Omar
- Post #15
- Forum: Announcements
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we draw a perpendicular bisector through the line joining U and U^2 and then seeing the...
we draw a perpendicular bisector through the line joining U and U^2 and then seeing the |Z-U^2|< |Z-U| , the < sign means it,s closer to U^2 so we shade the whole region towards U^2 i.e rightwards .the overlapping region we get is a part of a circle (the right segment of the circle) .yeah I...- M.Omar
- Profile post comment
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Yes I believe it,s correct . |Z<2| means any complex number with modulus less than 2 so we draw...
Yes I believe it,s correct . |Z<2| means any complex number with modulus less than 2 so we draw a circle of radius 2,centre the origin, and shade inside . |Z-U^2|< |Z-U| is achieved by first realizing |Z-U^2|=|Z-U| that distance of z(the variable complex number on argand diagram) from both U...- M.Omar
- Profile post comment
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Mathematics: Post your doubts here!
I asked a similar question from my teacher as well about a year before I think. He said it,s not a big deal and that both are correct.I do however still opt for drawing a dotted line for < or > sign. You could write as a side note a max of 5 words abt the point of drawing a dotted line in case u... -
so we see with radius of 1 it would touch line x=0 and thus its min arg would be pi/2 (90...
so we see with radius of 1 it would touch line x=0 and thus its min arg would be pi/2 (90 degress) ... for max arg we draw a line from origin to other end of diameter so that the total length opposite to origin is 2*radius=1 and length of base =3 to give angle with y axis = tan^-1(2/3) and...- M.Omar
- Profile post comment