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A2 Physics | Post your doubts here

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Assalamu alaikum,
Pls explain these questions:
November 2003, Paper 4, Q.4, part a. What's the point of connecting the diode in series rather than in parallel??
And solve this question too:
November 2003 , paper 4, Q.5 part b (2 ). Thanks :)
 
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Assalam Wa Alikum
Please Could Can one help me With this Q2 a (i) (ii) Why Are we using r Instead of r(square) in the formula
How Did M2 And Q2 Came Thank alot
http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w04_qp_4.pdf
Assalamu alaikum,
Force = GMm/r^2
We know that Energy = F.d ;
Energy = GMm/r^2 * r
Hence Energy = GMm/r;
Same goes for electric potential energy
That's one way of doing it.
Gravitational potential energy = mgh
Therefore Gravitational potential energy = m GM/r^2 * r - substituting values of g and h in the equation;
Therefore Gravitational potential energy = GMm/r
Electric potential energy = Vq
Therefore electric potential energy = Q/4(pi) (Epsilon nought ) r^2 *r - substituting values of V in the equation
Therefore electric potential energy = Qq/4(pi)( Epsilon nought ) r
 
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http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s08_qp_4.pdf
Can someone please explain the 4th c part..
Explanation given in the mark scheme seems to be kinda hard to understand!
AoA,
Maximum Force means maximum field strength should be applied
In other words,
F(max) α Field Strength (E)
The gradient of the graph gives field strength (E = V / x)
So
F(max) α gradient
gradient is max at x = 27 (Don't worry about the sign of gradient as we are not concerned abt direction here)
So F(max) is at x = 27
:)
 
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Anyone who can explain me why do v use the formula of kinetic energy over here.. ??
M/J 2010
2b(ii) Hence show that the initial energy stored in the steel strip before the mass is
released is approximately 3.2 mJ.
 
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Anyone who can explain me why do v use the formula of kinetic energy over here.. ??
M/J 2010
2b(ii) Hence show that the initial energy stored in the steel strip before the mass is
released is approximately 3.2 mJ.
AoA,
Which variant ?
And share the link please!
 
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Anyone who can explain me why do v use the formula of kinetic energy over here.. ??
M/J 2010
2b(ii) Hence show that the initial energy stored in the steel strip before the mass is
released is approximately 3.2 mJ.
It is actually the P.E that is 3.2mJ
But we use K.E formula because
K.E + P.E = constant at any instant [Law of conservation of energy]
Hope you got the point!
 
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well in this question Explain the main principles behind the generation of ultrasound to obtain diagnostic
information about internal body structures.
there is a put crystal cut to give resonance.....whereas it shud be like this that alternating p.d of frequency equal to natural frequency of oscillation crystal is applied so as to cause resonance and crystal cut so that resonance is in the US range.....what U guyx say?
 
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AoA,
Maximum Force means maximum field strength should be applied
In other words,
F(max) α Field Strength (E)
The gradient of the graph gives field strength (E = V / x)
So
F(max) α gradient
gradient is max at x = 27 (Don't worry about the sign of gradient as we are not concerned abt direction here)
So F(max) is at x = 27
:)

isnt the gradient max at x=5 cos the line's more steeper!!?
Sorry im kinda confused!
 
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Assalamu alaikum,
Force = GMm/r^2
We know that Energy = F.d ;
Energy = GMm/r^2 * r
Hence Energy = GMm/r;
Same goes for electric potential energy
That's one way of doing it.
Gravitational potential energy = mgh
Therefore Gravitational potential energy = m GM/r^2 * r - substituting values of g and h in the equation;
Therefore Gravitational potential energy = GMm/r
Electric potential energy = Vq
Therefore electric potential energy = Q/4(pi) (Epsilon nought ) r^2 *r - substituting values of V in the equation
Therefore electric potential energy = Qq/4(pi)( Epsilon nought ) r
Thanks A lot Bro
Jazzakallah Khair
 
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Q2 (b) (iii) the last line (R --> P)
 

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